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Q = 30 Kj = 30000 J
m = 1,4 kg
T1 = -10°C
Dit. T2..............?
penyelesaian :
Q = m.c.ΔT
Q = m.c. (T2 - T1)
30000 = 1,4. 2100. ( T2 + 10 )
30000 = 2940. ( T2 + 10 )
30000 = 2940T2 + 29400
30000 - 29400 = 2940 . T2
600 = 2940. T2
T2 = 600 / 2940
T2 = 0,20⁰C ⇒suhu akhirnya