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Sebanyak 300 ml larutan 0,2 M H2SO4 dicampur dengan 200 ml larutan 0,2 M NaOH. Berapa pH campuran itu?
Pembahasan
mol H2SO4 = 2. 300 . 0,2
= 120 mmol
mol NaOH = 200 . 0,2
= 40 mmol
H2SO4 + NaOH => NH3
mula2 120 40 -
reaksi 40 40 40
sisa 80 mmol 0 mmol 40 mmol
jadi sisa H2SO4 =
pH = - log H
= - log 1,6 x 10^-1
= 1 - log 1,6
jadi pH sisa H2SO4 = 1 - log 1,6
Semoga membantu :) D