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= 0,627 mol
nB(air) = 54 : 18
= 3
a. fraksi etanol
nA= nA : (nA+nB)
= 0,627 : (0,627+3)
= 0,627: 3,627
= 0,1728
b. fraksi mol air
nB= nB : (nA+nB)
= 3 : (0,627+3)
= 3 : 3,627
=0,827
=