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nH₂O = 100/18 = 5.56 mol
-> nNa⁺ = 23/80 = 0.29 mol
-> nOH⁻ = 17/80 = 0.21mol
-> nOH⁻ = 5.24 mol
= 0.29/0.5 = 0.58
= \frac{0.21+5.24}{5.56+0.5} [/tex] = 5.45/6.06 = 0.899