Sebanyak 100 ml larutan NH4OH 0,06 M dicampurkan ke dalam 400 ml C6H5COOH 0,015M yang pH-nya 3,5-log 3. Jika pH larutan campuran sebesar 7-log 2, pH larutan NH4OH mula-mula sebesar... ???
farisanrobbani
PH C6H5COOH = 3,5 - log 3 [H+] = 3 x 10^-3.5 [H+] = akar ka x M (3 x 10^-3.5)^2 = ka x 15 x 10^-3 ka = 9 x 10^-7/ (15 x 10^-3) ka = 6 x 10^-5 [H+] campuran = akar 10^-14 x ka/kb (2 x 10^-7)2 = 10^-14 x 6 x 10^-5/kb kb = 10^-14 x 6 x 10^-5/(4 x 10^-14) kb= 15 x 10^-6 [OH-] = akar kb x M NH4OH = akar 15 x 10^-6 x 6 x 10^-2 = akar 90 x 10^-8 = 3 x 10^-3,5 pOH = -log [OH-] = - log 3 x 10^-3,5 = 3,5 - log 3 PH = 14 - (3,5- log 3) = 10,5 + log 3...
[H+] = 3 x 10^-3.5
[H+] = akar ka x M
(3 x 10^-3.5)^2 = ka x 15 x 10^-3
ka = 9 x 10^-7/ (15 x 10^-3)
ka = 6 x 10^-5
[H+] campuran = akar 10^-14 x ka/kb
(2 x 10^-7)2 = 10^-14 x 6 x 10^-5/kb
kb = 10^-14 x 6 x 10^-5/(4 x 10^-14)
kb= 15 x 10^-6
[OH-] = akar kb x M NH4OH = akar 15 x 10^-6 x 6 x 10^-2 = akar 90 x 10^-8 = 3 x 10^-3,5
pOH = -log [OH-] = - log 3 x 10^-3,5 = 3,5 - log 3
PH = 14 - (3,5- log 3) = 10,5 + log 3...