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pH = 7,55, pKa = 7,55
+ 2 mL 1 M HCl
pH = ?
---
pH = pKa + log(base/acid)
7,55 = 7,55 + log(base/acid)
0 = log(base/acid)
base/acid = 1
mmol = 100 x 0,15 = 15 mmol
base = acid = 15 mmol
HCl = 2 x 1 = 2 mmol
B + HCl --> BH+ + Cl-
m 15 - 15 -
+2
r -2 -2 +2 +2
s 13 17
pH = pKa + log(base/acid)
pH = 7,55 + log(13/17)
pH = 7,433
cmiiw.