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Verified answer
Massa urea = 0,3 gramMassa air = 10 gr
Kb = 0,512°C/mol
Kf = 1,86°C/mol
Tb dan Tf ...?
ΔTb=M.Kb
ΔTb=0,3/60 x 1000/10 x 0,512
ΔTb=0,005 x 100 x 0,512
ΔTb=0,256
Tb=100°+0,256°
Tb=100,256°C (titik didih)
ΔTf=M.Kf
ΔTf=0,3/60 x 1000/10 x 1,86
ΔTf=0,005 x 100 x 1,86
ΔTf=0,93
Tf=0°-0,93°
Tf=-0,93°C (titik beku).