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α para el cobre es α = 17×10⁻⁶ (°C)⁻¹
α para el hierro es α = 12×10⁻⁶ (°C)⁻¹
si ΔT = 200 °C y sus longitudes iniciales son las mismas, entonces
Para el cobre:
ΔL = L₀αΔT
ΔL = (17×10⁻⁶ (°C)⁻¹ )(200 °C)(L₀)
(ΔL)c = (3,4×10⁻³)L₀
Para el hierro:
ΔL = L₀αΔT
ΔL = (12×10⁻⁶ (°C)⁻¹ )(200 °C)(L₀)
(ΔL)h = (2,4×10⁻³)L₀
(ΔL)c / (ΔL)h = (3,4×10⁻³)L₀ / (2,4×10⁻³)L₀ = 3,4/2,4 = 17/12
(ΔL)c / (ΔL)h = 17/12