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Verified answer
KINEMATIKA• GM
m = 2,5 ton = 2500 kg
g = 10 m/s²
v = 54 km/jam = 15 m/s
R = 25 m
Persamaan gaya di puncak bukit
ΣFₛ = m aₛ
m g - N = m v² / R
2500 • 10 - N = 2500 • 15² / 25
25000 - N = 22500
N = 2500 N ✓
besar gaya normal truk pafa saat di puncak bukit 2500 N.