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cara HORNER
4 -7 2 3
2 8 2 8
----------------------------------- (+)
4 1 4 11
hasilnya =(x-2)(4x² +x+4) +11
bersusun
4x² +x +4
_____________
x-2 /
/ 4x³ -8x² (untuk 4x²)
--------------
x² +2x
x² - 2x (untuk x)
--------------- (-)
4x + 3
4x - 8
-------------- (-)
11
cara : teorima sisa jika habis dibagi f(2)=0
maka
= 32 - 28 +4+3= 11 (sisa)
4 x³ -7 x² +2x +3 = (ax² + bx +c)(x-2)+11
= a x³ + (b-2a) x² +(c-2b) x -2c +11
nampak bahawa a=4
b-2a= -7 ...... b =1
c-2b = 2 ....... c= 4
= ( 4x² +x +4)(x-2)+11