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= [sin (2x³-3x)]³
y'= 3 sin (2x³-3x)² (6x²-3)
= 18x²-9 sin² (2x³-3x)
2. f(x) = cos (2x-4 / 3x+5)
f'(x) = -sin (2x-4 / 3x+5) (-5x-4 / 3x-2)
3. g(x) = x³ cos 2x
g'(x)= 3x² -sin 2x (2)
= 6x² -sin 2x