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x²+(p+1)x+3p+2=0
Akarnya -2. Akar yg lain.....
x1+x2=-b/a
-2+x2=-(p+1)/1
-2+x2=-(p+1)
x2=-(p+1)+2
x2=-p-1+2
x2=-p+1
x1.x2=c/a
-2.x2=3p+2/1
-2x2=3p+2
x2=3p+2/-2
-p+1=3p+2/-2
-2(-p+1)=3p+2
2p-2=3p+2
2p-3p=2+2
-p=4
p=-4
x²+(-4+1)x+3(-4)+2=0
x²+(-3)x+-12+2=0
x²-3x-10=0
(x-5)(x+2)=0
x1=5 dan x2=-2
Pilihan E.5
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