Question

Salah satu akar pers kuadrat mx²-3x+2=0 adalah dua kali akar yg lain. nilai m = ...

Answer 1

Mx^2 - 3x + 2 = 0
x1 = 2 x2
x1 + x2 = -b/a
2 x2 + x2 = 3/m
3 x2 = 3/m
x2 = 1/m maka x1 = 2 x2 = 2(1/m) = 2/m

x1 . x2 = c/a
(1/m) (2/m) = 2/m
(1/m) = (2/m)/(2/m)
1/m = 1
m = 1