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Cateto(b) = 11
Cateto(c) = 6
Hipotenusa(h) = ?
Por Pitagoras
h² = b² + c²
h² = 11² + 6²
h² = 121 + 36
h² = 157
h = √157
h = 12,53
Respuesta.
La hipotenusa del triangulo vale 12,53 aproximadamente