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Verified answer
Gerak Lurus Berubah BeraturanPercepatan benda:
v² = v₀² + 2aΔx
a = (v² - v₀²) / (2Δx)
= [(6 m/s)² - (4 m/s)²] / [2(10 m)]
= 1 m/s²
Lama benda menempuh jarak tersebut:
Δx = 1/2 (v + v₀)t
t = 2Δx / (v + v₀)
= 2(10 m) / (6 m/s + 4 m/s)
= 2 s
vo: 4 m/s
vt: 6 m/s
s: 10 m
Dit:
a) a
b) t
jawab
a) vt^2 = vo^2 + 2as
6^2 = 4^2 + 2a.10
36 = 16 + 20a
20 = 20a
a = 1 m/s^2
b)
vt = vo + at
6 = 4 + 1.t
2 = 1.t
t = 2 s