Zad 1
Piechur idzie ze stałą predkoscia s=2km. jaka droge przebędzie w czasie 0.5 h ?
Zad2
180 m/min-
600 cm/s-
54 km/h-
20m/s-
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v=s/t
s=2km=2000m
t=0,5h=30min=1800s
v=2000m/1800s
v=1,11 m/s
zad2
180m/min=180m/60s=3 m/s
600cm/s= 6m/s
54km/h= 54*1000m/3600s= 15m/s
20m/s