6.Oblisz średnia szybkośc ciała spadajacego swobodnie z wysokości 50 m,gdzie przyspiesznie ziemskie wynosi 10 m/s2.
Dane :
vo = 0 m/s
h = 50 m
g = 10 m/s2
szukane:
vśr = ?
vśr = s/t
s = 1/2 * at^2
s = h
a = g
h = 1/2 *gt^2 I*2
gt^2 = 2h /:g
t^2 = 2h/g
t = V(2h/g) = V(2*50m/10m/s2) = V10 s = 3,16 s
vśr = h/t = 50m/3,16s
vsr = 15,8 m/s
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Dane :
vo = 0 m/s
h = 50 m
g = 10 m/s2
szukane:
vśr = ?
vśr = s/t
s = 1/2 * at^2
s = h
a = g
h = 1/2 *gt^2 I*2
gt^2 = 2h /:g
t^2 = 2h/g
t = V(2h/g) = V(2*50m/10m/s2) = V10 s = 3,16 s
vśr = h/t = 50m/3,16s
vsr = 15,8 m/s