Buah durian massanya 2 kg jatuh bebas dari tangkainya memiliki energi mekanik 400 J . Jika percepatan gravitasi 10 m/s2 , tinggi buah durian , ketika energi kinetiknya 250 J adalah ... a. 7,5 m b. 20 m c. 80 m d. 150 m
indirakusuma
E Total = E potensial awal = 400 J E total = E potensial + E kinetik 400 = Epotensial + 250 Epotensial = 400 - 250 = 150 J
Epotensial = m.g.h 150 = 2 x 10 x h 150 = 20 h h = 150 : 20 = 7,5 m (A)
0 votes Thanks 1
dianutami3
EM = Ep + Ek 400 = Ep + 250 Ep = 150 m . g . h = 150 2.10 . h =150 h = 7,5 m
E total = E potensial + E kinetik
400 = Epotensial + 250
Epotensial = 400 - 250 = 150 J
Epotensial = m.g.h
150 = 2 x 10 x h
150 = 20 h
h = 150 : 20 = 7,5 m (A)
400 = Ep + 250
Ep = 150
m . g . h = 150
2.10 . h =150
h = 7,5 m