Sebuah mobil bergerak dengan kecepatan 72 km/jam. Sesaat kemudian pengendara mobil menginjak rem sehingga mobil diperlambat 2 m/s2. Jarak yang ditempuh mobil hingga berhenti adalah.… A. 400 m B. 300 m C. 200 m D. 100 m
karmen191
V= 72 km/jam = 20 m/s t= v/a = 20/2 = 10 s s= v×t = 20×10=200 m (c)
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Kiyeon
Dik. V0 = 72km/jam = 20 m/s a = -2 (karena diperlambat) Dit. S?
jawab... Vt = V0 + at 0 = 20 + (-2) t 20 = 2t t = 10s
Vt*2 = Vo*2 + 2as 0 = (20)*2 + 2(-2) s 0 = 400 +(-4s) 400 = 4s s = 100 meter
t= v/a = 20/2 = 10 s
s= v×t = 20×10=200 m (c)
a = -2 (karena diperlambat)
Dit. S?
jawab...
Vt = V0 + at
0 = 20 + (-2) t
20 = 2t
t = 10s
Vt*2 = Vo*2 + 2as
0 = (20)*2 + 2(-2) s
0 = 400 +(-4s)
400 = 4s
s = 100 meter