" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
t=1,5 s
g=9,8 m/s^2
Vp=0 m/s
Szukane:
h=?
Vk=?
s=(at^2)/2 <wzór na droge w ruchu jednostajnie przyspioszonym
s=(9,8m/s^2 * (1,5s)^2 )/2=(9,8 m/s^2 * 2,25 s^2)/2 = 11,025 m
--------------------------------------------------------------------------------------------------------
a=(Vk-Vp)/t <wzór na przyspieszenie
at=Vk-Vp
Vk=at+Vp
Vk=( 9,8m/s^2 * 1,5s ) + 0m/s = 14,7 m/s