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gdzie: Ek1 = m·V1²/2 , Ek2 = m·V2²/2 , W = F·d·cos180° = - F·d
m·V1²/2 - F·d = m·V2²/2 ---> F = m·(V1² - V2²)/(2·d)
F = 0.010·(600² - 400²)/(2·0.04) = 25 000 N = 25 kN