F=m x a sila = masa razy przyspieszenie m= 1 t=1000 kg a= Δv:Δt czyli zmiana predkosci w czasie a= (30-10):4= 20/4=5 m/s² F=1000 kg x 5 m/s²= 5000 N= 5 kN
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uczennica1313
A = ΔV:t a = (30m/s-10m/s):4s = 20m/s:4s = 5m/s^ a = F:m F = a*m F = 5m/s^*1t = 5m/s^*1000kg = 5000N = 5kN
a = (30m/s-10m/s):4s = 20m/s:4s = 5m/s^
a = F:m
F = a*m
F = 5m/s^*1t = 5m/s^*1000kg = 5000N = 5kN
F=m x a
sila = masa razy przyspieszenie
m= 1 t=1000 kg
a= Δv:Δt czyli zmiana predkosci w czasie
a= (30-10):4= 20/4=5 m/s²
F=1000 kg x 5 m/s²= 5000 N= 5 kN
a = (30m/s-10m/s):4s = 20m/s:4s = 5m/s^
a = F:m
F = a*m
F = 5m/s^*1t = 5m/s^*1000kg = 5000N = 5kN