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Wzór na wartość przyspieszenia:
a=ΔV/Δt
ΔV= 5m/s-2m/s
ΔV=3m/s
Δt=3s
a=3m/s / 3s
a=1m/s²
v1 = 2m/s
v2 = 5m/s
t1 = 0
t2 = 3s
a = ∆v/∆t
Rozwiązanie:
∆v = v2 - v1
∆v = 5m/s - 2m/s
∆v = 3m/s
∆t = 3s - 0
∆t = 3s
a = 3m/s : 3s
a = 1m/s² < do kwadratu
Odp. Przyśpieszeni wynosi 1 m/s²