Seorang anak berlari dgn kelajuan 4 m/s dlm waktu 5 menit lalu berhenti slama 60 detik untuk kemudian melanjutkan larinya kali ini dgn kelajuan 5 m/s slama 2 menit brp kelajuan rata rata ank tersebut + caranya
kaerasadewik
V = 4 m/s t = 5 menit = 5 x 60 = 300 s berhenti 60 s t lanjut = 2 x 60 = 120 s (v = 5 m/s)
jawab : v = s/t
v1 = s/t 4 = s/300 1200 m = s
v2 = s/t 0 = s/60 0 = s
v3 = s/t 5 = s/120 600 m = s
v rata2 = sigma jarak/sigma waktu =1200 + 0 +600/300 + 0 + 120 =1800/420 =4,29 m/s
t = 5 menit = 5 x 60 = 300 s
berhenti 60 s
t lanjut = 2 x 60 = 120 s (v = 5 m/s)
jawab :
v = s/t
v1 = s/t
4 = s/300
1200 m = s
v2 = s/t
0 = s/60
0 = s
v3 = s/t
5 = s/120
600 m = s
v rata2 = sigma jarak/sigma waktu
=1200 + 0 +600/300 + 0 + 120
=1800/420
=4,29 m/s