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Dit : Kecepatan awal ( Vo ) ... ? waktu ( t ) ... ?
Jawaban:
V² = Vo ² + ( 2 × a × s )
4² = Vo ² + ( 2 × (-2) × 12 )
16 = Vo² + ( -48 )
Vo² = 48 + 16 = √64 = 8 m/s.
Maka,
V= Vo + ( a×t )
4 = 8 + 2t
2t = 4
t = 2 sekon.
V = 4 m/s
a = - 2 m/s^2 (tanda minus karena perlambatan)
s = 12 m
Vo = ?
t = ?
V^2 = Vo^2 + 2.a.s
4^2 = Vo^2 + 2(-2).12
16 = Vo^2 - 48
16 + 48 = Vo^2
Vo^2 = 64
Vo = √64
Vo = 8 m/s
kecepatan awalnya = 8 m/s
V = Vo + a.t
4 = 8 + (-2)t
t = (4 - 8) / -2
t = 2 sekon
maka waktunya t = 2 sekon
semoga membantu