oblicz wysokośc na jaką dotrze kuleczka rzucona w górę z szybkością 5m/s
pomocy dam naj
h= v^2/2g
h= (5m/s)^2/(2*10m/s^2)
h=(25m^2/s^2)/(20m/s^2)
h= 1,25m
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h= v^2/2g
h= (5m/s)^2/(2*10m/s^2)
h=(25m^2/s^2)/(20m/s^2)
h= 1,25m