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ω = (4t³ + 2t² - 6) rad/s
Dit: α utk t = 2s sd t = 4s....?
jawab:
ω1 --> t1 = 2s
ω1 = (4t³ + 2t² - 6) rad/s
ω1 = (4.2³ + 2.2² - 6) rad/s
ω1 = (32 + 8 - 6) rad/s
ω1 = 34 rad/s
,
ω2 ---> t2 = 4s
ω2 = (4.4³ + 2.4² - 6) rad/s
ω2 = (256 + 32 - 6) rad/s
ω2 = 282 rad/s
maka:
α = (ω2 - ω1)/(t2 - t1)
α = (282 - 34)/(4-2)
α = 248/2
α = 124 rad/s²