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Va=10m/s
m1=200g=0,2kg
Ep=mgh
Ek=½mv²
zasada zachowania energi
½mv²=mgh
h=(½mv²)/mg
h=(½v²)/g
h=(1/2*100m²/s²)/10m/s²
h=50m²/s²*0,1s²/m
h=5m
Wzniesie się na 5m