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ro= (2i+3j) m/s
Dit : r= . . . ? t=2 s
Peny :
r = ro + ∫v dt
= 2i+3j + ∫8ti-2t²j
= (2i+3j) + (4t² i - 2/3 t³ j)
= (2i + 4t² i) - (3j + 2/3 t³ j)
= 6t² i - (3/3 + 2/3) t³
= 6t² i - (9 + 2 / 3) t³
= 6t² i - 3,66 t³
untuk t = 2s
rt=2 = 6t² i - 3,66 t³
= 6(2)² i - 3,66 (2)³
= 6 . 4 i - 3,66 . 8
= 24 i - 29,28 j <---- Jawaban
ro = 2 i + 3 j
ditanya : r (t = 2)
r = ro +
= (2 i + 3 j) +
= (2 i + 3 j) + (4.t² i - .t³ j)
= 2 i + 4t² i + 3 j - .t³ j
= (2 + 4.t²) i + (3 - .t³) j
untuk t = 2
r = (2 + 4 .2²) i + (3 - .2³) j
= (2 + 16) i + (3 - .8) j
= 18 i + ( 3 - ) j
= 18 i - j