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v0= 0
t= 3s
ditanya y
x ..?
maka
-y = V0y t - 1/2 gt²
-y = 0 - (1/2)10 3²
-y = 0 - 45
y = 45m ->jarak vertikal / tinggi tebing
x = V0 x t
x = 1,6m/s x 3
x = 4,8 m ->jarak horizontal / jrk kaki tebing ke kaki org