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V=500m/s
S=0,5m
F=?
t=?
S=Vot-at²/2
a=ΔV/t
S=Vot-ΔVt/2
t=S/(Vo-ΔV/2)=0,002s -> czas zagłębiania się
p=mV=0,006kg*500m/s=3kg*m/s
Δp=F*t
F=Δp/t
F=3/0,002=1500N=1,5kN->srednia siła
F=750\0,5=1500N sila oporu gruntu
Vo=a*t
a=Vo\t
s=Vo*t-a*t^2\2
s=Vo*t-Vo*t\2
s=(3\2)Vo*t
t=2s\3Vo=2*0,5\(3*500)=1\1500s=0,00067s
Mam nadzieje ze pomoglem :D