a) calcula la velocidad que el movil alcanza transcurrido ese tiempo
Respuesta:
[tex]v_f= v_0 + a \cdot t[/tex]
[tex]v_f=33.33m/s+ (4.00m/s^2)(5.00s)[/tex]
[tex]v_f=33.33m/s+ (20.00m/s)[/tex]
[tex]\boxed{v_f = 53.33m/s}[/tex]
b) ¿qué distancia recorre mientras el movil acelera?
[tex]d = 0.5\cdot(v_f+v_0)\cdot t[/tex]
[tex]d = 0.5\cdot(53.33m/s+33.33333336m/s)\cdot(5.00s)[/tex]
[tex]d = 0.5\cdot(86.67m/\cancel{s})\cdot(5.00\cancel{s})[/tex]
[tex]\boxed{d = 216.67m}[/tex]
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a) calcula la velocidad que el movil alcanza transcurrido ese tiempo
Respuesta:
[tex]v_f= v_0 + a \cdot t[/tex]
[tex]v_f=33.33m/s+ (4.00m/s^2)(5.00s)[/tex]
[tex]v_f=33.33m/s+ (20.00m/s)[/tex]
[tex]\boxed{v_f = 53.33m/s}[/tex]
b) ¿qué distancia recorre mientras el movil acelera?
Respuesta:
[tex]d = 0.5\cdot(v_f+v_0)\cdot t[/tex]
[tex]d = 0.5\cdot(53.33m/s+33.33333336m/s)\cdot(5.00s)[/tex]
[tex]d = 0.5\cdot(86.67m/\cancel{s})\cdot(5.00\cancel{s})[/tex]
[tex]\boxed{d = 216.67m}[/tex]