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Vo = 20 m/s
α = 45°
g = 10 m/s²
Xm = __ ?
Jika peluru ditembakkan dari tanah dan jatuh kembali di tanah
Jarak terjauh ke arah mana ????
Jarak tempuh horizontal maksimum (jangkauan)
Xm = Vo² sin 2α / g
= 20² sin 90° / 10
= 40 m ← jawaban
Tinggi maksimum
Ym = Vo² sin²α / 2g
= 20² sin²45° / 20
= 10 m