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Em=m*g*h+(m*Vdo potęgi2 )/2
Em=0,2kg*10m/s2*20m+(0,2kg*20m.s do kwadratu)/2= 40J+40J= 80 J
Dane:
m=0,2 kg
h=20 m
v= 20 m/s
Rozw.:
[Ep]= J
Ep= m*g*h= 0,2*10*20= 40 [J]
[Ek]= J
Ek= m*v² /2 = 0,2 * 20² /2= 0,2*400 /2 = 80/2= 40 [J]
[Ew]= J
Ew= Ep+Ek= 40+40= 80 [J]
Odp.: Energia mechaniczna tego ptaka wynosi 80 J
Ep = m*g *h
Ek = 1/2 * 0,2*20 2= 40
1/2 m *v 2=m*g *h
1/2 *0,2*400 = 0,2 *10 * h
h=20
Ep= 40
Em = 80