w jakim czasie kolaż przebędzie odległość 5 km jeśli jedzie z stałą prędkością 5m/s czas w minutach i sekundach
Dane:
s=5km=5000m
V=5m/s
Szukane:
t=?
Rozwiązanie:
V=s/t /*t
Vt=s /:V
t=s/V
t=5000m:5m/s=1000s
60s - 1min
1000s - xmin
x=(1000s*1min):60s=1000/60min=16 i 40/60min=16⅔min
dane:
s = 5 km = 5 000 m
v = 5 m/s
szukane:
t = ?
s = v * t /:v
t = s/v = 5000m/5m/s
t = 1000 s
-----------
1000 s = 1000 *1/60 min = 16,666 min
t = 16,7 min = 1000 s
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Dane:
s=5km=5000m
V=5m/s
Szukane:
t=?
Rozwiązanie:
V=s/t /*t
Vt=s /:V
t=s/V
t=5000m:5m/s=1000s
60s - 1min
1000s - xmin
x=(1000s*1min):60s=1000/60min=16 i 40/60min=16⅔min
dane:
s = 5 km = 5 000 m
v = 5 m/s
szukane:
t = ?
s = v * t /:v
t = s/v = 5000m/5m/s
t = 1000 s
-----------
1000 s = 1000 *1/60 min = 16,666 min
t = 16,7 min = 1000 s
==================