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w ruchu jednostajnym:
S = V*t
S = 10m/s*100s
S = 1000m
S = 1km
w ruchu jednostajnie przyspieszonym:
S = at²/2
a = 5m/s:10s
a = 0,5m/s²
S = (0,5m/s²*100s*100s)/2
S = (50m/s*100s)/2
S = 5000m/2
S = 2500m
S = 2,5km
całkowita droga:
S = 1km+2,5km
S = 3,5km
t jednostajny = 100 s
t jednostajne przyspiesz = 100 s
v jednostajnego = 10 m/s
v = s/t --> s = vt
s = (at²)/2 --> s = (Δvt²/Δt)/2
a = Δv/Δt
s = vt + (Δvt²/2
s = 10 × 100 + (5 × 100²/10)/2
s = 3500 m
Odp. Cialo przebylo droge 3,5 km.
v = s/t / × t
s = v × t
s = 100 × 10 = 1000 m
a = v/t
a = 5/10 = 0,5
s = 1/2 v × t²
s = ½ a × t²
s = 1/2 × 0,5 × 100² = 2500m
s całkowita = 1000 + 2500 = 3500 m