Question

Dua batang pegas identik dengan konstanta masing masing 500 N/m digantungi beban 4kg. jika g= 10 m/s², berapa pertambahan pegas apabila pegas disusun secara seri dan paralel ???

Answer 1

A. seri
1/ k total = 1/k1 + 1/k2
= 1/500 + 1/500
= 2/500
k total = 500/2 = 250

F = k . x
4.10 = 250 . x
40 = 250 x
x = 40 / 250
x = 0,16 m = 16 cm

b, Paralel
k tot = k1 + k2
= 500 + 500
= 1000

F = k . x
4.10 = 1000 . x
40 = 1000 x
x = 40 / 100
x = 0,04 m = 4 cm