[tex]A[/tex] - wypadnie co najmniej jedna szóstka
[tex]B[/tex] - na każdej kostce wypadła taka sama liczba oczek
[tex]P(A|B)=\dfrac{P(A\cap B)}{P(B)}[/tex]
[tex]|\Omega|=6^3[/tex]
[tex]|A\cap B|=1\\\\P(A\cap B)=\dfrac{1}{6^3}[/tex]
[tex]|B|=6\\P(B)=\dfrac{6}{6^3}=\dfrac{1}{6^2}[/tex]
[tex]P(A|B)=\dfrac{\dfrac{1}{6^3}}{\dfrac{1}{6^2}}}=\dfrac{1}{6^3}\cdot6^2=\dfrac{1}{6}[/tex]
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[tex]A[/tex] - wypadnie co najmniej jedna szóstka
[tex]B[/tex] - na każdej kostce wypadła taka sama liczba oczek
[tex]P(A|B)=\dfrac{P(A\cap B)}{P(B)}[/tex]
[tex]|\Omega|=6^3[/tex]
[tex]|A\cap B|=1\\\\P(A\cap B)=\dfrac{1}{6^3}[/tex]
[tex]|B|=6\\P(B)=\dfrac{6}{6^3}=\dfrac{1}{6^2}[/tex]
[tex]P(A|B)=\dfrac{\dfrac{1}{6^3}}{\dfrac{1}{6^2}}}=\dfrac{1}{6^3}\cdot6^2=\dfrac{1}{6}[/tex]