Rusuk2 balok yg bertemu pada sebuah pojok balok berbanding 4:4:1 Jika volume balok 432liter, luas permukaan balok adalah
DwitasariP
P : l : t = 4x : 4x : x volume = p × l × t 432 = 4x × 4x × x 432 = 16x³ x³ = 27 x = ∛27 = 3 cm p = 12 cm l = 12 cm t = 3 cm L balok = 2(pl+pt+lt) = 2 (12.12 + 12.3 + 12.3) = 2 (144+36+36) = 2.216 = 432 cm²
volume = p × l × t
432 = 4x × 4x × x
432 = 16x³
x³ = 27
x = ∛27
= 3 cm
p = 12 cm
l = 12 cm
t = 3 cm
L balok = 2(pl+pt+lt)
= 2 (12.12 + 12.3 + 12.3)
= 2 (144+36+36)
= 2.216
= 432 cm²