Question

Rozwiązywanie proporcji !!! POMOCY

Answer 1

a)

(2x+1)x = (x^{2}+5)2

2x^{2}+x = 2x^{2}+5 (skracasz 2x^{2})

x=5

 

b)

(x-\frac{1}{2})\frac{1}{3} = (3-2x)\frac{1}{12}

\frac{x}{3}-\frac{1}{6} = \frac{3-2x}{12} /*1

4x-2 = 3-2x

6x = 5

x= \frac{5}{6}

 

c)

(2x+1)5 = (4^{2}+2)3

10x+5 = 12x^{2}+6

-12x^{2}+10x-1=0

Δ=b^{2}-4ac

Δ=100-48

Δ=64

√Δ=8

x₁=\frac{-b-√Δ}{2a}

x₁=\frac{-10-8}{24}

x₁=\frac{3}{4}

 

x₂=\frac{-b+√Δ}{2a}

x₂=\frac{-10+8}{24}

x₂=\frac{1}{12}