Rozwiąz układ równań metodą podstawienia .
a )
{3y+2x=5
{x-y=5
b)
{y-x+4=3
{3x+2y=-7
c)
{3(x+2)+2(y-2)=1
{(x+2)-4(y-1)=1
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{x=5+y
{3y+2(5+y)=5
{x=5+y 3y+10+2y=5
5y= (-5)
y=(-1)
x=5+(-1)
{x=4
{y=(-1)
b) {y-x=-1
{3x+2y=(-7)
{y=x-1
{3x+2(x-1)= (-7) 3x+2x-2= (-7)
5x=(-5)
x = (-1)
y= (-1) -1
y= (-2)
{x= (-1)
{y= (-2)
c)
{ 3x+6+2y-4=1
{ x+2-4y+4=1
{3x+2y=(-1)
{x-4y= (-5)
{x=(-5) + 4y
{3( -5+4y) +2y= (-1) -15+12y+2y=(-1)
14y=14
y=1
x=(-5) + 4*1
{ x=(-1)
{y=1
Pozdrawiam :)