November 2018 1 41 Report
(a+b+1)^2=(a+b+1)(a+b+1)=\\ =a^2+ab+a+ab+b^2+b+a+b+1=\\ =a^2+b^2+2ab+2a+2b+1
rozwiąz ten sam przyklad korzystajac ze wzoru na kw. sumy
(c+d)^2\ \ \ \ \ \ \ \ \ \ gdzie:\ \ \ \ \ c=a+b\ \ \ \ \ \ d=1
czyli
(a+b+1)^2= [(a+b)+1]^2=...

z gory dziekuje
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