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Rownanie sprzeczne.
a = 1
b = 8
c = 15
Δ = b² - 4ac = 8² - 4 * 1 * 15 = 64 - 60 = 4
√Δ = √4 = 2
x₁ = ( - b - √Δ)/2a = (- 8 - 2)/2 = - 10/2 = - 5
x₂ = (- b + √Δ)/2a = (- 8 + 2)/2 = - 6/2 = - 3
x² - 4x + 6 = 0
a = 1
b = - 4
c = 6
Δ = b² - 4ac = (- 4)² - 4 * 1 * 6 = 16 - 24 = - 8
ponieważ Δ < 0 to równanie nie ma pierwiastków a zbiorem rozwiązań jest zbiór pusty