rozwiąz równanie (x-3)(x+6)=0
powinno wyjśc -6.
(x-3)(x+6)=0
x²+6x-3x-18=0
x²+3x-18
a=1,b=3,c=-18
Δ=b²-4ac
Δ=3²-4*1*(-18)
Δ=9+72
Δ=81
√Δ=√81=9
x₁=-b+√Δ/2a=-3+9/2=3
x₂=-b-√Δ/2a=-3-9/2=-6
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(x-3)(x+6)=0
x²+6x-3x-18=0
x²+3x-18
a=1,b=3,c=-18
Δ=b²-4ac
Δ=3²-4*1*(-18)
Δ=9+72
Δ=81
√Δ=√81=9
x₁=-b+√Δ/2a=-3+9/2=3
x₂=-b-√Δ/2a=-3-9/2=-6