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-x²+2x+15=0
Δ=4+60=64
√Δ=8
x₁= -10/-2= 5
x₂= 6/ -2= -3
x ∈ <-3 ; 5>
a= -1; b = 2; c =15
Δx = b² - 4ac
Δx = 2² - 4 *(-1)*15
Δx = 4 + 60 = 64
√Δx = 8
x₁= -b - √Δx/2a
x₂= -b + √Δx/2a
x₁= -2 - 8/-2
x₁= -10/-2 = 5
x₂= -2 + 8/-2
x₂= 6/-2 = -3
Odp. -x²i2x+15≥0 <=> x∈ <-3, 5>
Δ=b²-4ac
Δ=4-[4(-1)×15]
Δ=64
√Δ=8
x1= -b-√Δ/2a
2-8/-2=3
x2=-b+√Δ/2a
2+6/-2 =-4
ramiona paraboli skierowane w dół :>
x <-4,3>