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t²-5t+4=0
Δ=25-4*4=9
t=1/2*(5-3)=1 v t=1/2*(5+3)=4
x²=1 v x²=4
x=-1 v x=1 v x=-2 v x=2
Odp. x∈{-2,-1, 1, 2}