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5=4a+b (2)
Wyznaczam b z (1)
b=3-2a (3)
Podstawiam (3) do (2)
5=4a+3-2a
5-3=2a
2a=2
a=1 (4)
Podstawiam (4) do (3)
b=3-2
b=1
- 2a+b=3
____________
2a =2
a=1
4a+b=5
b=5-4a
b=5-(4x1)
b=5-4
b=1
a=1
b=1