Rozwiaz układ równań (x+3)²-(y-1)²=(x-y)(x+y)² 3x-7y=0
3x=7y/:3
x=7/3y
x²+6x+9-y²+2y-1=x²-y²
x²+6x-y²+2y-x²+y²=1-9 (x² i y²skracaja sie)
zostaje
6x+2y=-8
za x podstawiamy
6·7/3y+2y=-8
14y+2y=-8
16y=-8 /:16
y=-1/2
podstawiamy do x=7/3y
x=7/3·(-1/2)
x=-7/6=-1 1/6
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3x=7y/:3
x=7/3y
x²+6x+9-y²+2y-1=x²-y²
x²+6x-y²+2y-x²+y²=1-9 (x² i y²skracaja sie)
zostaje
6x+2y=-8
za x podstawiamy
6·7/3y+2y=-8
14y+2y=-8
16y=-8 /:16
y=-1/2
podstawiamy do x=7/3y
x=7/3·(-1/2)
x=-7/6=-1 1/6