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x= -2 y=1
lub
x=-4 y=-3
x+3 ≠ 0
x ≠ -3
D = R \ {-3}
(2x+5)(x+3) = -x-1
2x² + 6x + 5x + 15 = -x - 1
2x² + 11x + x + 15 + 1 = 0
2x² + 12x + 16 = 0 /:2
x² + 6x + 8 = 0
x² + 2x + 4x + 8 = 0
x(x + 2) + 4(x + 2)
(x + 4)(x + 2) = 0
x₁ = -4
y₁ = 2 * (-4) + 5 = -8 + 5 = -3
x₂ = -2
y₂ = 2 * (-2) + 5 = -4 + 5 = 1
{x₁ = -4
{y₁ = -3
{x₂ = -2
{y₂ = 1