rozwiaz rownanie;2x-3\2x+1=3x-2\3x+1
\ozn.kreske ulamkowa
2x-3\2x+1=3x-2\3x+1
(2x-3)(3x+1)=(2x+1)(3x-2)
6x²+2x-9x-3=6x²-4x+3x-2
6x²-7x-3-6x²=-4x+3x-2
-7x-3+4x-3x+2=0
-6x=1/(-6)
x=-1/6
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2x-3\2x+1=3x-2\3x+1
(2x-3)(3x+1)=(2x+1)(3x-2)
6x²+2x-9x-3=6x²-4x+3x-2
6x²-7x-3-6x²=-4x+3x-2
-7x-3+4x-3x+2=0
-6x=1/(-6)
x=-1/6